Question

1
If 42x=
32
then x =

Answer 1

Concept Used:

$(a^{m})^{n}=a^{mn}\\\frac{1}{a^{m}}=a^{-m}$

When bases are equal then powers are also equal.

Solution:

$4^{2x}=\frac{1}{32}\\=>(2^{2})^{2x}=\frac{1}{2^{5} }\\=>2^{4x}=2^{-5}\\=>4x=-5\\=>x=-\frac{5}{4}$

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