Question

1. If 5 cos = 6 sin , find 12 sin −3 cos
$\frac{12 sin −3 cos }{12 sin +3 cos }$
2. If 5 cos − 12 sin = 0, evaluate sin +cos
2 cos −sin

Answer 1

Answer:

Correct option is

A

13

5cosΘ=6sinΘ

tanΘ=

6

5

Now,

12sinΘ+3cosΘ

12sinΘ−3cosΘ

Multiply and divide by cosΘ,

=

12tanΘ+3

12tanΘ−3

=

12(

6

5

)+3

12(

6

5

)−3

=

60+18

60−18

=

78

42

=

13

7