Math, asked by bmaruti989, 19 days ago

1. If 7 kg onions cost 140 rupees, how much must we pay for 12 kg onions?

2. If 600 rupees buy 15 bunches of feed, how many will 1280 rupees buy?

3. For 9 cows, 13 kg 500 g of food supplement are required every day. In the proportion, how much will be needed for 12 cows?

4. The cost of 12 quintals of soyabean is 36,000 rupees. How much will 8 quintals

5. Two mobiles cost 16,000 rupees. How much money will be required to buy 13 mobiles ? ​

Answers

Answered by kyraaJuliette
2

1) 12*140/7 = 240 rupees

2) 1280*15/600 = 32 bunches of feed.

3) 9 cows- 13500 grams of food

12 cows- 12*13500/9 = 18000 grams = 18 kg

4) 8*36,000/12 = 24,000 rupees

5) 13*16000/2 = 1,04,000 rupees

Answered by dayanidhisharma19
1

Answer:

240 rupees, 32 bunches, 18 kg, 24000 rupees, 104000 rupees

Step-by-step explanation:

1.

Given 7 kg onions cost 140 rupees,

Implies 1 kg onion cost 140/7 rupees = 20  rupees

Implies 12 kg onions cost 20×12 rupees = 240 rupees

2.

If 600 rupees buy 15 bunches

Implies in 1 rupees buy 15/600 bunches = 1/40 bunches

Implies in 1280 rupees buy 1280×1/40 bunches = 32 bunches

3.

For 9 cows food need 13 kg 500 g = 13.5 kg

Implies 1 cow need food = 13.5/9 kg = 1.5 kg

Implies 12 cows need food  = (12×1.5) kg = 18 kg

4.

The cost of 12 quintals of soyabean is 36,000 rupees

Implies The cost of 1 quintals of soyabean is 36,000/12 rupees = 3000 rupees

Implies The cost of 8 quintals of soyabean is 3000×8 rupees = 24000 rupees

5.

Given 2 mobiles cost 16,000 rupees

Implies 1 mobile cost 16,000/2 rupees = 8000 rupees

Implies 13 mobiles cost 8000×13 rupees = 104000 rupees

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