1. If 9° term of an AP is zero, prove that its 29° term is twice ts 19" term
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Answer:
a + 8d = 0
a = -8d
29th term = a + 28d
19th term = a + 18d
2(19th term) = a + a + 36d
= a + 36d - 8d
2(19th term) = a + 28d = 29th term
LHS = RHS
Hence proved
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