Question

1) if 9000 rupees are invested at 10 p.c.p.a. for 3 years. find its interest.​

Answer 1

Answer:

Interest = Rs. 2700

Step-by-step explanation:

principal = 9000

R = 10

N = 3

$i \: = \frac{pnr}{100} = \frac{9000 \times 10 \times 3}{100} \\ = 90 \times 10 \times 3 \\ = 900 \times 3 = 2700$

simple interest = 2700

Answer 2

Before, finding the answer. Let's find out how we can find the answer.

• In this question, we are supposed to find the Interest.
• So, to find the Interest, we must use the formula of :

$\tt Interest = \dfrac{p \times r \times t}{100}$

• Where, you have to multiply the Principal, Rate, and Time first. Then, we must divide it by 100.

_________________________

Given :

• Principal = Rs. 9000
• Rate = 10%
• Time = 3 years

To find :

• Interest

Solution :

Now,

$\tt Interest = \dfrac{p \times r \times t}{100}$

               $\tt = \dfrac{9000 \times 10 \times 3}{100}$

               $\tt = \dfrac{90 \not 0 \not0 \times 10 \times 3}{1 \not 0 \not 0}$

               $\tt = \dfrac{90 \times 10 \times 3}{1}$

               $\tt = \dfrac{900 \times 3}{1}$

               $\tt = \dfrac{2700}{1}$

               $\tt = 2700$

Therefore, Interest is Rs. 2700.