Question

1) if (a^2-1) x^2+(a-1) x+a^2-4a+3=0 is an identity in x, then find the value of a. ​

Answer 1

Answer:

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AND YOUR ANSWER IS

a=1

Step-by-step explanation:

$({a}^{2} - 1) {x}^{2} + (a - 1)x - 4a + 3 = 0$

(a 2 −1)x2+(a−1)x+a 2−4a+3=0

(a−1)[(a+1)x2+x+(a−3)]=0

a=1.