Question

1. If a= 2, b = -2, find the value of a² + ab + b²​

Answer 1

Answer:

a²+ab+b²=4

Step-by-step explanation:

substituting value of a and b in a²+ab+b², we get

= (2)²+(2)(-2)+(-2)²

= 4-4+4

=0+4

=4

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Answer 2

Answer:

Hence the value of  $a^{2} +ab+b^{2}$  is 4.

Step-by-step explanation:

As per the data provided in the given question .

The given data is as follows,

Given:-a² + ab + b²​

Value of a is 2 and value of b is -2.

We have to find the value of $a^{2} +ab+b^{2}$

Given equation is,

$a^{2} +ab+b^{2}$

Now we will substitute the value of a and b in above equation.

Further, we get

$=2^{2}+2\times(-2)+(-2)^{2}$

Now we will substitute square of 2 is 4 and square of -2 is 4.

We get,

$=4+2\times(-2)+4$

The multiplication of 2 into -2 is 4 and output sign will be negative i.e. -4

$=4+(-4)+4$

The multiplication of (+) into (-) is (-)

$=4-4+4\\=0+4\\=4$

Hence the value of  $a^{2} +ab+b^{2}$  is 4.