Question

1. If a=2 b=3 c=1 evalute
a) 2ab2+3bc2-4ca2+9abc​

Answer 1

Given
a=2
b=3
c=1
2ab^2+3bc^2-4ca^2+9abc
[2a{b^2-2ca}+3bc{c+3a}]
put the value of a,b,c
[2*2{3^2-2*1*2}+3*3*1{1+3*2}]
[4{{9-4}+9{7}]
[4*5+9*7]
[20+63]
= 83

Answer 2

Answer:

given : a = 2

b =3

c = 1

putting their value in the following

2ab² + 3bc² -4ca² + 9abc

(2×2×3)² + ( 3×3×1)²- (4× 1×2)² + ( 9×2×3×1)

(12)² +( 9)² - (8)² + 54

144 + 81-64 + 54

= 215