Question

1. If à =2i + 4j - 5k find magnitude of à answerrrrrrrrrrrr pleaseeeee
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Answer 1

Answer:

Given, vector A = 2i + 4j - 5k.

Here, i, j and k are unit vectors along positive X, Y and Z axes respectively.

So, IA| = |√[(2^2) + (4^2) + {(-5)^2]| = |-√451

= √45

So, unit vector along A = (A cap) = (A / IAI)

= (1/ √45) * (2i + 4j - 5k)

= 0.149 * (2i + 4j - 5k)

(0.298i + 0.596j - 0.745k).

Answer 2

Answer:

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