1. If A = 3î +2j-k and ß = 2î +j-k, then calculate AB
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Explanation:
a=2i+3j+4k
b=i+j−k
c=i−j+k
a×(b×c)=(a⋅c)b−(a⋅b)c
=(2−3+4)b−(2+3−4)c
=3b−c
=(3
i
^
+3
j
^
−3
k
^
)−(i−j+k)
=2
i
^
+4
j
^
−4
k
^
a.(a×(b×c))=2×2+3×4+4×(−4)=0
therefore,
a×(b×c) is perpendicular to a
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