Question

1. If A=a2+6, B=3a2+a+2 and C=a2+4a, then find A+B-C with proper statment

Answer 1

Step-by-step explanation:

A=a^2+6

B=3a^2+a+2

C=a^2+4a

A+B-C=

$= ({a}^{2} + 6) + (3 {a}^{2} + a + 2) - ({a }^{2} + 4a) \\ = {a}^{2} + 6+ 3 {a}^{2} + a + 2 - {a }^{2} - 4a \\ = 3 {a}^{2} - 3a + 8$