Question

(1) if a and B are the zeroes of quadratic polynomial f(x) = 6x2+x-2, then a + B=?
(a) 1/6
(b) 1/8
(c) 1/6
(d) 5​

Answer 1

Answer:

6x^2 + x - 2

Step-by-step explanation:

6x^2 + (4-3)x - 2

6x^2 + 4x - 3x - 2

2x(3x+2) - 1(3x+2)

(2x-1)(3x+2)

x = 1/2 = a

x= -2/3 = b

a+b

1/2 -2/3

(3-4)/6

-1/6