1. If a and B are the zeros of the quadratic polynomial f(x) = x2 - 1, find a quadratic polynomial whose zeroes are
2a/b and 2b/a
Please solve this
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8
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Step-by-step explanation:
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ak171:
i think you hasn't read the question
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5
Answer:
Step-by-step explanation:
f[x] = x^2 -1 = [x+1] [x-1]
1 and -1 are zeroes
now a=1 and b= -1
2a/b = -1 and 2b/a = -1
so p[x] = [x+1] [x+1]
p[x] = x^2 + 2x +1
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