Question

1. If a and bare rational numbers find the value of a and b x5+12 =a+b√/10√5-√2

Answer 1

Answer:

3+13−1×3−13−1

\frac{ { (\sqrt{3} - 1) }^{2} }{ { \sqrt{3} }^{2} - {1}^{2} } = \frac{3 + 1 - 2 \sqrt{3} }{3 - 1}32−12(3−1)2=3−13+1−23

\frac{4 - 2 \sqrt{3} }{2} = \frac{2(2 - \sqrt{3 }) }{2}24−23=22(2−3)

= 2 - \sqrt{3}=2−3

comparing with a+b/3

a=2 b=-1

Answer 2

Answer:

hey mate! hope it helps u

Step-by-step explanation:

(√2 - √3)/(3√2 + 2√3) = a + b√6

LHS = (√2 - √3)(3√2 -2√3)/(3√2 +2√3)(3√2 - 2√3)

= { √2(3√2 -2√3) -√3 (3√2 -2√3)}/{(3√2)²-(2√3)² }

={ 6 -2√6 -3√6+6 }/{ 18 - 12}

={ 12 - 5√6 }/6

=2 - (5/12)√6 = a + b√6

so, a = 2 and b = -5/12