Question

1. If a, ß are the zeroes of the polynomial 9x²-1 the value of a²+B²
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Answer 1

Answer:

Given quadratic polynomial is

9x

2

−6x−3=0

⇒9x

2

−9x+3x−3=0

⇒9x(x−1)+3(x−1)=0

⇒(9x+3)(x−1)=0

⇒x=

3

−1

or1

here,α=

3

−1

andβ=1

also,a=9;b=−6;c=−3

hence,α+β=

3

−1

+1=

3

2

=

9

−(−6)

=

a

−b

and,α.β=

3

−1

.1=

3

−1

=

9

−3

=

a

c

Hence proved