Question

1)) if a block of 5kg is lying on the ground,
then the thrust on the surface of the
ground due to the weight of the block:​

Answer 1

Answer:

6m/s² ( PLZ MARK ME BRAINLIEST)

Explanation:

From figure, there is no acceleration in vertical direction. So, Applying Newton's Law in vertical direction, we get

          N=mg  

               =50N

Maximum value of Friction f  

max

​

=μN=0.2×50=10 N

Since, f  

max

​

≤F

So, sliding will happen, and kinetic friction will act, i.e.  

        f  

kinetic

​

=μN=10N

Step 3: Newton’s Law for finding acceleration

Applying Newton's second law on block, in horizontal direction

(Taking rightward positive)

∑F=ma

⇒F−f  

kinetic

​

=ma

⇒F−μmg=ma

⇒40−0.2×5×10=5a

⇒a=6m/s  

2

 

Hence acceleration of the block will be 6m/s  

2

Answer 2

Answer:49N

Explanation:mg 5kg *9.8ms2=49N

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