Question

1)if a bulb of 60 w is connected across a source of 220 V.
find the current drawn by it .
2)A bulb of 40 w is connected across a source which of 220 v .find the resistance of the bulbs

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Answer 1

Answer:-

(1) Current drawn by the bulb is 0.27 A .

(2) Resistance of the bulb is 1210 Ω .

Explanation:-

Number (1) :-

We have :-

• Power of the bulb = 60 W

• Potential difference = 220 V

________________________________

Now, we know that :-

i = P/V

⇒ i = 60/220

⇒ i = 6/22

⇒ i = 0.27 A

Number (2) :-

We have :-

• Power of the bulb = 40 W

• Potential difference = 220 V

________________________________

Now, we know that :-

P = V²/R

⇒ 40 = (220)²/R

⇒ 40R = 48400

⇒ R = 48400/40

⇒ R = 1210 Ω

Answer 2

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

1)if a bulb of 60 w is connected across a source of 220 V.

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$Data \: of \: the \: question$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

$P = 60 W$

$V= 220 V$

$I = ?$

$We \: know \: that$

$P = V I$

$Therefore$

$I = \frac{P}{V} = \frac{60W}{220V} \\ \\ = \frac{3}{11} A = 0.2727A$

$The \: current \: drawn \: by \: the \\ \\ \: bulbs \: is \: =$

$\frac{3}{11} A = 0.2727A$

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

2)A bulb of 40 w is connected across a source which of 220 v .find the resistance of the bulbs

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$Data \: of \: the \: question$

$P = 40 \: W$

$V= 220 V$

$R = ?$

$We \: know \: that$

$P = VI = V \frac{V}{R} = \frac{ {V}^{2} }{R}$

$R = \frac{ {V}^{2} }{P}$

= (220 V)²\40 W

=220× 220\40 Ω

=200× 200\2×20Ω

= 11 × 110Ω

=1210 Ω

The resistance of the bulbs is 1210Ω