1) If a current of 0.8 A is passed through a wire having resistance
30 ohm for 4 minute, calculate the heat generated in the wire in joul.
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2
H = I²RT = 0.8² × 30 × 4 × 60 = 0.64 × 30 × 4 × 60
= 64 × 3 × 4
= 64 × 12
= 768Ana.
rocky5631:
hii
Answered by
1
Current,I = 0.8 A
Resistance,R = 30 ohm
Time,t = 4 min = 4× 60 = 240 s
Using Joule's heating law,
H = I^2 RT
= 0.8×0.8×30×240
On solving, we get,
H = 4608 J
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