Question

1) If a current of 0.8 A is passed through a wire having resistance
30 ohm for 4 minute, calculate the heat generated in the wire in joul.​

Answer 1

H = I²RT = 0.8² × 30 × 4 × 60 = 0.64 × 30 × 4 × 60

= 64 × 3 × 4

= 64 × 12

= 768Ana.

Answer 2

Current,I = 0.8 A

Resistance,R = 30 ohm

Time,t = 4 min = 4× 60 = 240 s

Using Joule's heating law,

H = I^2 RT

= 0.8×0.8×30×240

On solving, we get,

H = 4608 J