Question

1 . if a= i+j+k,b=2i+2j+2k,c= 3i+3j+3k then |abc| plz slove
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Answer 1

Answer:

It is verified that a × (b × c) ≠ (a × b) × c.

Explanation:

a × b

=

¯

¯

¯

¯

¯

¯

¯

i j k

1 −2 4

2 −2 3

¯

¯

¯

¯

¯

¯

¯

= i(−2 × 3) − i(−2 × 4) − j(1 × 3)

+k(1 × −2) + j(4 × 2) − k(2 × −2)

= −6i + 8i − 3j − 2k + 8j + 4k

= 2i + 5j + 2k

Answer 2

$a = \sqrt{i + j + k \: \: }$

$b = \sqrt{2i + 2j + 2k}$

$c = \sqrt{3i + 3j + 3k}$

$then |abc| =$

$a + b + c = \sqrt{6i + 6j + 6k} =$

$a + b + c = \sqrt{18}$

THUS THIS IS THE ANSWER