Question

1. If a quadratic equation has no real roots the value of the discriminant could be:
A-3
BO
2. If the value of the discriminant of a quadratic equation is then the equation has.
A. O roots
C. 2 roots
B. 1 root
D. 3 roots
3. Find p so that x2 - 4x +p=0 has one root.
C.4
D.-4
4. What is the value of the discriminant for the equation px2 + x +=0?
C. 12 - Apr
A. 92 - 4pr​

Answer 1

Given :    a quadratic equation has no real roots

To Find : value of the discriminant could be

-3

0

4

- 4

Solution:

ax² + bx + c = 0

D = b² - 4ac

D =  discriminant

D < 0  no real roots

D = 0  Roots are real and Equal

D > 0 unequal and real roots

a quadratic equation has no real roots  Hence D < 0

so D can be - 3  or - 4

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