Question

1 If a transversal intersect two lines such, that the bisectors of a pair of corresponding angles are parallel, then prove that lines are parallel​

Answer 1

Answer:

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Step-by-step explanation:

The transversal AD intersects the two lines PQ and RS at points B and C respectively. BE is the bisector of ∠ABQ and CF is the bisector of ∠BCS.

As, BE is the bisector of ∠ABQ, then,

∠ABE=

2

1

∠ABQ

In the same way,

∠BCF=

2

1

∠BCS

Since BE and CF are parallel and AD is the transversal, therefore, by corresponding angle axiom,

∠ABE=∠BCF

2

1

∠ABQ=

2

1

∠BCS

∠ABQ=∠BCS

Therefore, by the converse of corresponding angle axiom,

PQ∥RS.

Answer 2

given: A transversal AB intersects two lines PQ and RS such that ∠ PLM = ∠ SML

To prove: PQ || RS

Proof: ∠ PLM = ∠ SML (given) ....(i)

∠ SML = ∠ RMB ... (ii) (vertically opposite angles)

From equations (i) and (ii),

∠ PLM = ∠ RMB

As these are corresponding angles and corresponding angles equal only if given lines PQ and RS are parallel.

∴ PQ || RS