Question

1) If a triangle and square are on the same
base and between. The same parallels, then
the ratio of the triangle to the area of the
Suquare is
b) 1:2
:
d) 3:1
a) 1:4​

Answer 1

Question:-

• If a triangle and a square are on the same base and between the same parallels then the ratio of area of triangle to the area of the square is :

Options:-

A)

• $\boxed{ \frac{1}{4} \: }$

B)

• $\boxed{ \sf \blue{ \frac{1}{2} \: ✓}}$

C)

• $\boxed{ \frac{2}{3} \: }$

D)

• $\boxed{ \frac{3}{1} \: }$

Explanation:-

• Area of square = L²
• Area of triangle = $\frac{1}{2} \: (lb) \: \times \: lh$

$\boxed{ \sf \red{ LB \: = \: LH \: = \: L}}$

• because triangles & squares are on same base & between same parallels.

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: Triangle\: : \: Square \: =\: \frac{ \frac{1}{2} \: \times \: L\: \times \: L }{ \: L\: \times \: L} }} }\\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: \frac{ \: Triangle}{Square} \: = \: \frac{1}{2} }} }\\ \\\end{gathered}\end{gathered}$

So, ratio is $\frac{1}{2}$