Question

1.
if a wire of length 1 metre placed in uniform magnetic field 1.5 Tesla at angle 30° with magnetic
field, the current in a wire 10 amp then force on a wire will be
(1) 7.5 N
(2) 1.5 N
(3) 0.5 N
(4) 2.5 N​

Answer 1

1) 7.5 N !

Hope it helps ❤️

Answer 2

Answer:

The force on the wire will be 7.5N i.e.option (1).

Explanation:

The force on the wire in a magnetic field is given as,

$F=I(L\times B)=BIL sin\theta$                (1)

Where,

F=force acting on the wire

L=length of the wire

B=magnetic field in which wire is present

I=current flowing through the wire

θ=angle between the length and magnetic field in which the wire is present

The values given in the question are,

L=1 meter

B=1.5T

I=10 A

θ=30°

Sin30°=1\2

Lets put the required values in equation (1);

$F=1.5\times 10\times 1\times \frac{1}{2}=7.5N$

Hence, the force on the wire will be 7.5N i.e.option (1).