Question

1) If ∆ ABC – ∆ PQR and AB : PQ = 2 : 3 Find
A(∆(∆ABC))
A(∆(∆PQR))​

Answer 1

Answer:

4/9

Step-by

Given :

Triangle ABC=PQR

AB:PQ

2:3

According to theorem of ares of similar triangle "when two triangle are similar , the ratio of areas of those triangle is equal to the ratio of the square of their corresponding sides"

Therefore, A(ABC)/A(PQR) = AB/PQ= 2square / 3 square = 4/9