Math, asked by SanyaShaikh, 2 months ago

1. If alpha,beta, gama, delta are the roots of the equation x^4 + x^3 + x^2 + x + 1 = 0 then the value of (1 - alpha)(1-Beta)(1-gama)(1-delta) is equal to
a. 6
b. 5
C. 4
d. 3​

Answers

Answered by jadhavgaurav6282
0

Answer:

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Answered by vijetaavsingh
1

Answer:

42x+29=0

f(x)=x4−2x3+2x2+1

Let the transformed equation be g(y)=0.

If y is a root of the new equation, then

y=2+x1

So, x=y−21

And hence, f(x)=f(y−21)=0 

⇒(y−21)4−2(y−21)3+2(y−21)2+1=0

Multiplying throughout by (y−2)4, we get

g(y)=(y−2)4+2(y−2)2−2(y−2)+1=0

After expansion and rearrangement, we get

g(y)=y4−8y3+26y2−42y+29

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