1. If alpha,beta, gama, delta are the roots of the equation x^4 + x^3 + x^2 + x + 1 = 0 then the value of (1 - alpha)(1-Beta)(1-gama)(1-delta) is equal to
a. 6
b. 5
C. 4
d. 3
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Answer:
42x+29=0
f(x)=x4−2x3+2x2+1
Let the transformed equation be g(y)=0.
If y is a root of the new equation, then
y=2+x1
So, x=y−21
And hence, f(x)=f(y−21)=0
⇒(y−21)4−2(y−21)3+2(y−21)2+1=0
Multiplying throughout by (y−2)4, we get
g(y)=(y−2)4+2(y−2)2−2(y−2)+1=0
After expansion and rearrangement, we get
g(y)=y4−8y3+26y2−42y+29
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