Question

1)If an angle is 28° less than its complement, find its measure.

2)If an angle is 30° more than one half of its complement, find measure of the angle.

Answer 1

Let the angle be x°
A/q

x°=90-x°-28
=62-x°
x°+x°=62
2x=62
x=31

Hence the Angle is=31°


2) Let the angle be x°

A/q
x=30+(90-x)/2

x=60+90-x/2

x=150-x/2

2x=150-x

3x=150

x=50.

Hence the angle is 50°



Hope it will help u.

Answer 2

$<b>Heya Mate </b>$

1)Let the angle be x.

Then other angle =28-x

Given,x+x-28=90

2x=118

x=59

So,the angle will be 90-59=31°


2) Let the angle be y.

Other angle will be (y/2)+30

Given, y+(y/2)+30=90

(2y+y)/2=60

3y/2=60

y=60×2/3

y=40°

So,the measire of the angle =90-40=50°

$<marquee>☺☺☺☺☺☺☺☺</marquee>$