1.If b = 3, then any integer can be expressed as a =(a) 3 q, 3 q+ 1, 3 q + 2 (b) 3 q (c) none of the above (d) 3 q+ 1
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Solution:
From given, we have
b=3
Given is a constant and is equated to 3.
If considering b as a variable, and as it is equated to 3, then it implies that, b is a
multiple of 3.
Therefore, from given options, only the second option describes b as a multiple of 3.
So, we can take q=1,2,3,4,. b=39
when q = 1, b = 3 x 1= 3
when q = 2, b = 3 x 2 = 6
when q = 3, b = 3 x 3 = 9 and so on.
Therefore, option (B) 3q is correct.
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