Question

1. If cot = 15/8, evaluate
(2+ 2sin)(1-sin)/(1 + cos)(2 - 2cos)
​

Answer 1

Step-by-step explanation:

cot0 =15/8

which is base/perpendicular =15/8

SO WE HAVE TO FIND HYPOTENUSE ,

BY PYTHAGORAS THEOREM,

so hypotenuse =17

ATQ,

(2+2sin)(1-sin)(1+cos)(2-2cos)

where sin =p/h,=8/17,cos=15/17

now,putting the values,

(2+2×8/17)(1-8/17)(1+15/17)(2-2×15/17)

=(4×8/17)(1-8/17)(1+15/17)×15/17

=32/17×9/17×32/17×15/17

=138240/83521