Question

1. If each side of a triangle is doubled, then find percentage increase in its area.​

Answer 1

Answer:

300percent

Step-by-step explanation:

hope it helps you

Answer 2

Answer:

300%

Step-by-step explanation:

Semi-perimeter of the triangle, s= a+b+c/2

Area of triangle = √s(s−a)(s−b)(s−c)

When each side is doubled, the new sides are 2a,2b,2c.

Hence, new s′ = 2a+2b+2c/2

=2( a+b+c / 2 ) =2s

New area A′ = √2s(2s−2a)(2s−2b)(2s−2c)

= √2×2×2×2×s(s−a)(s−b)(s−c)

= 4√s(s−a)(s−b)(s−c)

∴ % change in Area = (A - A′ / A) × 100

= 4√s(s−a)(s−b)(s−c) - √s(s−a)(s−b)(s−c) / √s(s−a)(s−b)(s−c) ×100

= 4−1 / 1 ×100

=300%