Question

1. If f:R+R is defined by f (x) = x2 - 3x + 2, then f (x2 – 3x - 2) =
a) x4 + 1
b) x4 - 2x2 +2
c) x4 + 2x + 2
d) x4 - 6x3 +2x2 +21x + 12​

Answer 1

Answer:

We have , f(x) = x2 - 3x + 2

f(f(x)) = f(x2 - 3x + 2)

= (x2 - 3x + 2)2 -3(x2-3x+2)+2

= x4 + 9x2 + 4 - 6x3 - 12x + 4x2 - 3x2 + 9x - 6 + 2

= x4 - 6x3 + 10x2 - 3x

f(f(x)) = x4 - 6x3 + 10x2 - 3x

Step-by-step explanation:

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