1) if f(x) = 16+ + log2 x, find f(1\4)
Answers
Answered by
11
Step-by-step explanation:
f(x)=(16)
x
+log
2
x
First put x=
4
1
into above f
x
f(
4
1
)=(16)
1/4
+log
2
(
4
1
)
⇒(4
2
)
1/4
+log
2
(
2
1
)
2
∵logm
n
=nlogm
⇒4
2/4
+2log
2
(
2
1
) [(a
m
)
n
1
=a
n
m
] ∵log
m
1
=−logm
⇒4
2
1
+2(−log
2
2) ∵log
m
m=1
f(
4
1
)⇒2−2(1)=0
Now put x=
2
1
into above f
x
f(
2
1
)=(16)
1/2
+log
2
(
2
1
)
=4+(−log
2
2)4−1=3 Ans.
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