Question

1
If f'(x)= e* + 1/1+x^2
and f(0) =1, then find f(x).
1+x2​

Answer 1

Step-by-step explanation:

ANSWER

→f(0

−

)=lim

x→0

f(0−x)=lim

x→0

1−e

−1/x

1+e

−1/x

as e

−∞

→0

⇒lim

x→0

1−e

−1/x

1+e

−1/x

=

1

1

=1=f(0)⇒ Left continues

f(0

+

)=lim

x→0

f(0+x)=lim

x→0

1−e

1/x

1+e

1/x

×

e

−1/x

e

−1/x

=lim

x→0

e

−1/x

−1

e

−1/x

+1

=−1



=f(0)⇒ Not right continues

⇒(A)