Math, asked by Anonymous, 1 year ago

1). if figure 3.8,<ACD in an exteriors angle of ABC_B=40°,<A=70°.find the measure of <ACD....

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Answered by missphoenix

0

<ACD= B+A= 40°+70°=110°

Answered by kumarmangalam

1

exterior angle of a triangle= sum of opposite angle of trangle
angleACD=angleA+angleB
angleACD=70°+40°
=110°

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