Math, asked by ayush0017, 1 year ago

1.
If HCF of x^2 - x - 6 and x^2 + 9x + 14 is x + m,
then the value of m is​

Answers

Answered by ananthukrishnan456
1

Step-by-step explanation:

using factorisation

x^2 - x - 6 = (x-3)(x+2)

x^2 + 9x + 14 = (x+7)(x+2)

therefore HCF = x + 2

given that HCF = x+m

therefore the value of m=2

Answered by Anonymous
1

Answer:

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x^2-x-6

= (x+2)(x-3)

x^2+9x+14

= (x+2)(x+7)

if x+m=x+2

so the value of m iz 2.

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