Question

1. If I have a 3.9-liter sample of gas at 35 kPa and I increase the pressure to 45 kPa what is the new volume of the gas?
2.If I have a 2.5 liter sample of a gas at 225 kPa of pressure and I increase the volume of the gas to 8.9 liters, what is the pressure of my gas at this new volume?
3.A sample of gas takes up 5.6 liters at a temperature of 15 degrees celsius, at what temperature will the gas occupy 25 liters of space?
4. They had to chase down a hydraulic lift the boat that was pushing down on a 2.8 m² piston (A1) with a force of 3700N (F1). What force (F2) needs to be exerted on a .072 piston (A2) to lift the boat?

Please leave how you solved the problem so we know how to solve it in the future!

Answer 1

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1).

Given P1 = 35 kPa

V1 = 3.9L

P2 = 45 kPa

V2 = new volume = ?

P1V1 = P2V2

35×3.9 = 45×V2

136.5/45 = V2

V2 = 3.0333

new volume = 3.033 L

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2)

Given P1 = 225 kPa

V1 = 2.5 L

P2 = new pressure = ?

V2 = 8.9 L

P1V1 = P2V2

225×2.5 = P2 × 8.9

562.5/8.9 = P2

P2 = 63.02

new pressure = 63.02

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3)

V1 = 5.6 L

T1 = 15°C = (15+273)= 288K

V2 = 25 L

T2 = ?

V1/T1 = V2/T2

5.6/288 = 25/T2

T2 = (25×288)/5.6

T2 = 7200/5.6

T2 = 1285.71 K

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4)

Given A1 = 2.8 m²piston

F1 = 3700N

A2 = 0.072 m² piston

F2 = ?

by Pascal law

F1/A1 = F2/A2

3700/2.8 = F2/0.072

(3700×0.072)/2.8 = F2

F2 = 266.4/2.8

F2 = 95.14 N