Question

1.
If (k+1)x²+3/2x= 7 is a quadratic equation, then k cannot be equal to​

Answer 1

Quadratic equations

If $ax^{2}+bx+c=0$ be a quadratic equation, then it must be understood that $a$ cannot be $0$, because when $a=0$, the coefficient of the square term vanishes and this makes the equation a linear equation of the form $bx+c=0$

Given: the equation $(k+1)x^{2}+\frac{3}{2}x=7$ is a quadratic equation

To find: the value of $k$

Solution:

• Since $(k+1)x^{2}+\frac{3}{2}x=7$ is a quadratic equation, the coefficient of the leading term $x^{2}$ can not be zero.

• i.e., $k+1\neq 0$
• $\Rightarrow k\neq -1$

Answer: $k\neq -1$

Answer 2

Answer:

k can't be equal to -1 as it will be linear equation