Question

1. If length is twice of breadth of a rectangle and perimeter is 48 cm then find the

area of rectangle.

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Answer 1

Question:-

• If length is twice of breadth of a rectangle and perimeter is 48 cm.

To find:-

• Find the area of rectangle.

Solution:-

Given:-

• Let breadth be 'x'.
• Let length be '2x'.
• Perimeter is 48 cm.

Answer:-

Perimeter = 2(l+b)

48 = 2(2x-x)

48 = 4x - 2x

-4x - 2x = -48

-2x = -48

x = -48/-2

x = 24

Hence,

• Breadth = 24cm.
• Length = 2x = 2(24) = 48cm