Question

1. If load of 400 N can be lifted by a force of 100 N using a lever, then calculate the mechanical advantage. 2. A man of mass 40 kg sits at a distance of 80 cm from the fulcrum of a seesaw, Calculate the mass of another man who sits at a distance of 16 cm from the fulcrum such that the seesaw is balanced. ​

Answer 1

Answer:

1. If the load of 400 N can be lifted by a force of 100 N using a lever,

Mechanical advantage is 4

2. A man of mass 40 kg sits at a distance of 80 cm from the fulcrum of a seesaw, The mass of another man who sits at a distance of 16 cm from the fulcrum to balance the seesaw is 200kg

Explanation:

1.

Given,

Load = 400 N           Effort = 100 N

The mechanical advantage of a machine is the ratio of its load and effort.

it is given by the formula,

Mechanical advantage (M.A) = $\frac{Load}{Effort}$

Substitute the  values,

M.A = $\frac{400}{100} = 4$

2.

Given,

Mass of man on the first side ( $m_{1}$ )   = 40 kg

Distance of  $m_{1}$ frm fulcrum ($d_{1}$)  = 80 cm = 0.8 m

Distance of  $m_{2}$ frm fulcrum ($d_{2}$)  = 16 cm = 0.16 m

Using the principle of moments we can write,

Clockwise moment = Anticlockwise moment

that is,

$m_{1}d_{1} = m_{2} d_{2}$

 $m_{2} = \frac{m_{1}d_{1}}{d_{2}}}$

Substituting the values,

$m_{2} = \frac{40\times0.80}{0.16}$

     =  200 kg