Question

1. If mass percentage of sugar in an aqueous
solution is 20%, then the mass of water present
in 320 g of such solution is
(1) 300 g
(2) 180 g
(3) 256 g
(4) 220 g​

Answer 1

(3)

mass % = wa /wa +wb ×100

Answer 2

Answer:

The correct answer is option (3).

Explanation:

Mass percentage of sugar in an aqueous  solution = 20%

Mass of solution = 320 g

Mass of solute that is sugar = x

$20\%=\frac{x}{320 g}\times 100$

$x=\frac{20\times 320 g}{100}=64 g$

Mass of water = m

Mass of solution = mass of water + mass of sugar

320 g = m + 64 g

m = 320 g - 64 g = 256 g

The mass of water present  in 320 g of such solution is 256 grams.