1. If n(A) = 10, n(B) = 12 and n(AB) = 6, then find n(AB).
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Let's write all the given values
- n( A ) = 10
- n( B ) = 12
- n( A ∩ B ) = 6
- n( A ∪ B ) = ?
Now, recall the equation in which given values are included
- n( A ∪ B ) + n( A ∩ B ) = n( A ) + n( B )
Substituting the given values we get
n( A ∪ B ) + 6 = 10 + 12
n( A ∪ B ) = 22 - 6 = 16
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