Question

1) If n(A) = 45, n (B) = 52, n(AUB)
=70, find n(ANB).*​

Answer 1

Answer:

We know that,

n(A)+n(B)-n(A intersection B)=n(A union B)

Here,

n(A)=45

n(B)=52

n(A union B)=70

By substituting above values in the formula we get,

=》45+52-n(A intersection B)=70

=》97-n(A intersection B)=70

=》97-70=n(A intersection B)

=》27=n(A intersection B)

=》n(A intersection B) = 27

The correct answer is 27.

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Answer 2

Step-by-step explanation:

Here is the solution:

There is a mathematical relation between union and intersection of Two sets,

Let A and B be two sets, Then the formula will be,

n(AUB)= n(A)+ n(B) - n(AnB),

Given data,

n(A) = 45 ,

n(B) = 52 ,

n(AUB) = 70,

n(AnB) = ?,

Substituting them in above Formula,

=> 70 = 45 + 52 - n(AnB) ,

=> 7O = 97 - n(AnB)

=> n(AnB) = 97 - 70

=> n(AnB) = 27

Therefore The a answer is 27,

Hope you understand, Have a Great day :D,