Question

1.
If one of the zeroes of the quadratic polynomial 2+3+kis 2, then the waive
of k is
(a) 10
(b) -10
(d) -2​

Answer 1

Answer:

$2 {x}^{2} + 3x + k \\ \\ \implies \: 2 \times {(2)}^{2} + 3 \times 2 + k = 0 \\ \\ \implies \: 8 + 6 + k = 0 \\ \\ \implies \: k = - 14$