1 If one point of radius is at the centre of the circle, the another point is on the 2 If diameter of a circle is 5 cm, then its radius is 3. A circle has centre. 4. Draw a circle of 3 cm and find diameter of the circle. (2)
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Step-by-step explanation:
Clearly ∠OPT=90o
Applying Pythagoras in △OPT, we have
OT2=OP2+PT2
⇒132=52+PT2
⇒PT2=169−25=144
⇒PT=12 cm
Since lengths of tangents drawn from a point to a circle are equal. Therefore,
AP=AE=x(say)
⇒AT=PT−AP=(12−x)cm
Since AB is the tangent to the circleE. Therefore, OE⊥AB
⇒∠OEA=90o
⇒∠AET=90o
⇒AT2=AE2+ET2 [Applying Pythagoras Theorem in △AET]
⇒(12−x)2=x2+(13−5)2
⇒144−24x+x2=x2+64
⇒24x=80
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