1. If OP is the bisector of ZAOC and OQ is the bisector of ZBOC then find ZPOQ.
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Also we can simply say that ∠POQ=½(
∠AOC+∠BOC)= ½∠AOB
The way how I have done it is explained given below step by step:
Step-by-step explanation:
Let, m∠AOC=x and m∠BOC=y
Given that, OP and OQ are the bisectors of ∠AOC and ∠BOC
Therefore, ∠POQ= ∠POC + ∠COQ
= x/2 + y/2
= ½(x+y)
= ½(∠AOC+ ∠BOC)
= ½∠AOB
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