Math, asked by vatss4829, 8 months ago

1. If P = 3x2 - 7x-8, Q = x+8.x - 3, R = -5x2 – 3x + 2, find :
(i) P-Q-R
(i) P+Q-R​

Answers

Answered by jitemath
0

Answer:

P = 3x2 - 7x-8, Q = x+8.x - 3, R = -5x2 – 3x + 2, find (i) P-Q-R

(ii) P+Q-R​

Step-by-step explanation:

(i) P-Q-R

=(3x^2-7x-8)-(x^2+8x-3)-(-5x^2-3x+2)

=(3-1+5)x^2+(-7-8+3)x+(-8+3-2)

=7x^2-12x-7

(ii) P+Q-R​

=(3x^2-7x-8)+(x^2+8x-3)-(-5x^2-3x+2)

=(3+1+5)x^2+(-7+8+3)x+(-8-3-2)

=9x^2+4x-13

Answered by athulyavincent
0

Step-by-step explanation:

hope it helps you .hope

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