1. If p=999, the value of (p(p2+3p+3)+1)1/3 is
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Answered by
5
Hii friend,
P = 999
Therefore,
[P(P²+3P+3) +1)1/3
= [999(999)²+3×999+3) +1 ) 1/3
= 999[998001+2997+1]1/3
= 999(1000999)1/3
= 999998001 ×1/3
= 333332667 Ans.
HOPE IT WILL HELP YOU.... :-)
P = 999
Therefore,
[P(P²+3P+3) +1)1/3
= [999(999)²+3×999+3) +1 ) 1/3
= 999[998001+2997+1]1/3
= 999(1000999)1/3
= 999998001 ×1/3
= 333332667 Ans.
HOPE IT WILL HELP YOU.... :-)
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0
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