Question

1.If P(a/3 ,4) is the midpoint of the line segment joining the points Q(-6, 5) and R(-2, 3) , then find the value of 'a'. 2.A line intersects y-axis and x-axis at the points Pand Q respectively. If (2,-5)is the midpoint of PQ then find the coordinates of P and Q respectively.

Answer 1

Answer:

$\red { Value \: of \: a } \green {=-12}$

Step-by-step explanation:

$Given \: P(\frac{a}{3},4)\:is \:the \: midpoint \\of \:the \: line \: segment\: joining \:the \:points \\Q(-6,5)\:and \:R(-2,3)$

$Mid \:point \: of \: the \:line \: segment \\joining\:the \: points \:(x_{1},y_{1})\:and \:(x_{2},y_{2})\\= \left(\frac{x_{1}+x_{2}}{2} , \frac{y_{1}+y_{2}}{2}\right)$

$\frac{a}{3} = \frac{-6+(-2)}{2}$

$\implies \frac{a}{3} = \frac{-6-2}{2}$

$\implies \frac{a}{3} = \frac{-8}{2} = -4$

$\implies a = 3 \times (-4)$

$\implies a = -12$

Therefore.,

$\red { Value \: of \: a } \green {=-12}$

•••♪

Answer 2

Answer:

a= -8

Step-by-step explanation:

mark me brainliest