Question

1. If p + q = 10 and pq = 21, find
(i) p2 - q2
(ii) p3 + q3​

Answer 1

Answer:

hi uoky7 iotdob jodio tong ons. o ym. i

Answer 2

Answer:

(i) 40

(ii) 370

Step-by-step explanation:

p + q = 10

pq = 21

The factors of 21 are 1, 3, 7, 21.

Since 3 + 7 = 10

And 7 x 3 = 21

p = 7

q = 3

p^2 - q^2

=> 7^2 - 3^2

=> 49 - 9

=> 40

p^3 + q^3

=> 7^3 + 3^3

=> 343 + 27

=> 370