Question

1) If p(t) = t^3-1 find the values of P(1), P(-1), P (o) P(2),(P-2).​

Answer 1

Answer:

you can do it by putting values 1,-1,0,2,-2 in place of t

like p(t) = t^3-1

p(1) = t^3-1

= 1^3-1

=1-1

=0

and so on

Answer 2

Answer:

hey mate, here is your answer hope it was help full

Step-by-step explanation:

→ Let p ( t) = t ³ - 1

→ p ( 1) = ( 1) ³-1 = 1 -1 = 0

→ p( -1)  = ( -1) ³ -1 = -1 -1 = - 2

→ p ( 0) = 0 ³  - 1 = 0 -1 = -1

→ p ( -2) = ( -2) ³ - 1 = -8 - 1 = -9

this is the answer both answer are correct

i will , text one more

Given , p(t) = t³ - 1

Now, We are to find the values of p(1), p(–1),

p(0), p(2), p(–2) .

So,

→ p(1) = (1)³ - 1 = 1 - 1 = 0

→ p(2) = 2³ - 2 = 8 - 2 = 6

→ p ( 0 ) = 0³ - 1 = 0 - 1 = -1

→ p(-1) = (-1)³ - 1 = -1-1 = -2

→ p(-2)³ = (-2)³ - 1 = -9

→ Hope helped!

thank you