1) if p(x)=8x^2-9x+9, find the difference between sum of its zeros and product of zeros
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Hey
Here is your answer,
8x^2-9x+9=0
Sum of zeroes = -b/a
Alpha + beta = 9/8
Product of zeroes = c/a
Alpha x beta = 9/8
Difference = 9/8-9/8
=0
Hope it helps you!
Here is your answer,
8x^2-9x+9=0
Sum of zeroes = -b/a
Alpha + beta = 9/8
Product of zeroes = c/a
Alpha x beta = 9/8
Difference = 9/8-9/8
=0
Hope it helps you!
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